Abowling bowl is thrown off the top of a building. determine distance the ball has fallen after falling for 3.0 s. remember, the gravitational acceleration (g) is 9.8 m/s2. (hint: d = ½gt2) a 3 kg lunch box is pushed across the lunch table. the acceleration of the lunch box is 2.0 m/s2. what was the net force applied to the lunch box? (hint: f = ma) show all your work! find the weight of a 10 kg rock. remember, acceleration due to gravity is -9.8 m/s2. (hint: w = mg) show all your work!

Question 1:

d = distance the bowling ball has fallen = ?

g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²

t = time of fall for the ball = 3.0 s

distance the ball has fallen is given as

d = (0.5) g t²

inserting the above values in the equation above

d = (0.5) (9.8 m/s²) (3.0 s)²

d = (0.5) (9.8 m/s²) (9.0 s²)

d = (4.9 m/s²) (9.0 s²)

d = 44.1 m

Question 2 :

m = mass of the lunch box pushed = 3 kg

a = acceleration of the lunch box = 2 m/s²

F = net force acting on the lunch box

as per newton's second law , net force is given as

F = ma

F = 3 x 2

F = 6 N

Question 3 :

m = mass of rock = 10 kg

g = acceleration due to gravity = 9.8 m/s²

W = weight of the rock

weight of rock is given as

W = mg

W = 10 x 9.8

W = 98 N