If an object is thrown up at an initial velocity of 9.8 m/s , how long will it take to fall back to the ground?

t = 2 s

Explanation:

As we know that when object comes back to its initial position then the displacement of the object will be zero

so here we can say by kinematics equation

here we know that

now from above equation we know

so from above equation we have

t = 2 s

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

the force on the thing and the distance the force moves the thing