A70 kg man is walking at a speed of 2 m/s. what is his kinetic energy?

The kinetic energy is 140 joules

The parameters given in the question are

mass= 70 kg

velocity= 2m/s

Kinetic energy= 1/2mv²

= 1/2 × 70 × 2²

= 0.5 × 70 × 4

= 140 joules

Hence the kinetic energy is 140 joules

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Kinetic energy = 1/2 (mass) (speed squared)

KE = 1/2 (70kg) (2m/s)^2

KE = (35 kg) (4 m^2/s^2)

KE = (140) kg-m^2/s^2

That's 140 Newton-meter

or

140 Joules

the pull of gravity on the rocket decreases