Physics, 29.06.2019 01:30 jayzelgaspar8441

Two tugboats pull a barge across the harbor. one boat exerts a force of 7.5 x 10^4n north, while the second boat exerts a force of 9.5 x 10^4n at 15 degrees north of west. precisely, in what direction does the barge move?

Answers: 1

Show answers

Answers

Answer from: CoreyHammond584

The barge move due to the pulling force of two boats as 47.3 degrees in north-west direction.

What is force?

Force is the effect of pull or push due to which the object having a mass changes its velocity.

The force is of two types-

Push-When the force applied in the direction of motion of the object, then the force is called the push force. Pull- When the force applied in the opposite direction of motion of the object, then the force is called the pull force.

Two tugboats pull a barge across the harbor.

In the given situation, one boat exerts a force of $7.5 \times 10^4\rm N$ in the direction of north and the the second boat exerts a force of $9.5 \times 10^4\rm N$ N at 15 degrees north in the direction of west.

For this situation the total force acting on the north direction can be given as,

$F_N=7.5\times10^4+9.5\times10^4(\sin 15^o)\\F_N=7.5\times10^4+2.459\times10^4\\F_N=9.96\times10^4$

Now the total force acting on the west direction can be given as,

$F_W=9.5\times10^4(\cos15^o)\\F_W=9.18\times10^4$

The tangent theta for this situation can be given as,

$\tan \theta=\dfrac{9.96\times10^{4}}{9.18\times10^{4}}\\\theta=\tan^{-1}(1.0849)\\\theta=47.3^o$

Thus, the barge move due to the pulling force of two boats as 47.3 degrees in north-west direction.

Learn more about the force here;

link

Two tugboats pull a barge across the harbor. one boat exerts a force of 7.5 x 10^4n north, while the

Answer from: tristan4233

The barge moves at an angle 47.3°North of West.

The tug boats exert forces in different directions on the barge and the barge moves in the direction of the resultant force.

Draw a diagram representing the forces, as shown in the figure attached. The tug boat 1 exerts a force F₁ along North while the tug boat 2 exerts a force F₂ at an angle of 15° North of west.

Resolve the forces along the North and the West.

The force acting along the North is given by,

$F_N=F_1+F_2sin15\\ =(7.5*10^4N)+(9.5*10^4 N*sin15)\\ =9.96*10^4N$

The force along the West is given by,

$F_W=F_2cos15=(9.5*10^4N)cos15\\ =9.18*10^4N$

The resultant force F makes an angle θ North of West.

Therefore, from the diagram,

$tan\theta =\frac{F_N}{F_W} \\ =\frac{9.96*10^4N}{9.18*10^4N} \\ =1.0849$

Hence,

$\theta =tan^-^1(1.00849)\\ =47.3^o$

Thus, the barge moves in a direction 47.3° North of West.

Answer from: Quest

asthenosphere and convection

Answer from: Quest

The reflection of the candle in the concave mirror formed an upside-down virtual image that is smaller than the candle.in other words. the answer is the third option, c

Another question on Physics

Physics, 21.06.2019 18:40

What are the phases shown in a and d called?

Answers: 1

Answer

Physics, 22.06.2019 01:00

4. who was the first one to measure the speed of light and conclude that it is finite? 5. who was the first philosopher who thought the speed of light is finite? 13. what is the speed of light numerically? 14. give an example of something moving faster than light 15. give an example for some particles or waves that

Answers: 1

Answer

Physics, 22.06.2019 12:00

For the car in the picture ,in which direction is the normal force? -into the screen -down -out of the screen -up

Answers: 2

Answer

Physics, 22.06.2019 13:00

What causes the formation of ocean currents?

Answers: 2

Answer

You know the right answer?

Two tugboats pull a barge across the harbor. one boat exerts a force of 7.5 x 10^4n north, while the...