A145-g baseball is thrown so that it acquires a speed of 25 m/s. what was the net work done on the ball to make it reach this speed, if it started from rest?

The net work done is 45.31J

Work done on a body is equal to an increase in energy of a body

The formula for work done is

W = force x distance

Given:

mass = 145g

Speed = 25m/s

We will need to find the distance using one of the equations of motion

Force = m x g

Convert the mass from g to kg by dividing by 1000

m = 145g

m = 145/1000

m = 0.145kg

Force = 0.145 x 10

Force = 1.45N

Work done = 1.45 * 31.25

Work done = 45.31J

Hence, the net work done is 45.31J

Read more about work done at

link

When the ball has left your hand and is flying on its own, its kinetic energy is

KE = (1/2) (mass) (speed²)

KE = (1/2) (0.145 kg) (25 m/s)²

KE = (0.0725 kg) (625 m²/s²)

KE = 45.3 Joules

If the baseball doesn't have rocket engines on it, or a hamster inside running on a treadmill that turns a propeller on the outside, then there's only one other place where that kinetic energy could come from:  It MUST have come from the hand that threw the ball.  The hand would have needed to do  45.3 J  of work on the ball before releasing it.

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