Acar travels at uniform acceleration over a distance of 440.0 m. its initial velocity is 11.0 m/s. what is its final velocity after 20.0 s? 207.0 m/s 11.0 m/s 22.0 m/s 33.0 m/s

x=v0t+1/2at^2

x=440 m

v0=11 m/s

t=20 s

Solve for a

440=11(20)+1/2a20^2

440=220+1/2a*400

220=1/2a*400

440=400a

1.1=a

Now we can use V=V0+at

V=11+1.1*20

V=33 m/s

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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double the distance = divide strength by 4