A5.00 kg mass is attached to a spring on a horizontal frictionless surface. the elastic constant of the spring is 37.9 n/m. if the mass is 39.0 cm right of the equilibrium point and moving at speed 7.4 m/s, find the total mechanical energy

45.6 i think i'm not sure pls double check

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j