What is the restoring force of a spring with a spring constant of a 4a and a stretched displacement of 3b?

Thus, the restoring force is - 12 a b.

Given:

Spring constant = 4 a

Stretched displacement = 3 b

To find:

Restoring force = ?

Formula used:

The restoring force is given by,

F = -k x

Where F = restoring force

spring constant = k = 4 a

stretched displacement = x = 3 b

Solution:

The restoring force is given by,

F = -k x

Where F = restoring force

spring constant = k = 4 a

stretched displacement = x = 3 b

F = - (4 a) (3 b)

F = - 12 a b

Thus, the restoring force is - 12 a b.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

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