Mary is at the top of a 25 m steep slide. she is then pushed and starts accelerating at a rate of 4.3 m/s"2. how long will it take her to get to the bottom of the slide?  

Answer

3.4 s

Explanation

The question can be solve by using the 2nd Newton's law of motion.

s = ut + 1/2at²

Before she is pushed, the  initial velocity is zero.

u = 0

Now the equation becomes

s = 0 + 1/2at²

s = 1/2at²

25 = 1/2 × 4.3 × t²

50 = 4.3t²

t² = 50/4.3

  = 11.628

t = √11.628

   = 3.4 s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.