The center fielder for the school's baseball team throws a 0.150-kg baseball towards home plate at a speed of 22.0 m/s and an initial angle of 40.0°. what is the kinetic energy of the baseball at the highest point of its trajectory?

The value of kinetic energy of the baseball thrown by the school's team at the highest point of its trajectory is 21.3 J.

Kinetic energy is a type of energy, which a body is posses due to its motion. The kinetic energy of a body can be found with the following formula,

Here, (m) is the mass of the body, and (v) is the speed of the body.

The speed of the baseball is 22 m/s. The initial angle of the ball is 40.0 degrees. Thus the horizontal component of the velocity at the highest point can be given as,

The vertical component of the velocity at the highest point is zero, Thus, we have only a horizontal component of velocity acting on the body at the highest point.

As, the mass of the baseball is 0.150 kg. Thus, put the values in the above formula as,

Hence, the value of kinetic energy of the baseball thrown by the school's team at the highest point of its trajectory is 21.3 J.

Learn more about the kinetic energy here;

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at the highest point of the trajectory of the ball only horizontal component of the velocity will remain as there is no acceleration in horizontal direction.

But due to gravity in vertical direction the vertical component of the velocity will become zero at the highest point

so here we can say that at highest point we will have

now for the kinetic energy we can say

here we know that

now the kinetic energy will be given as

so kinetic energy will be 21.3 J

answer; (arch); good luck

12000j is work done