You are moving a heavy wooden table (596.08kg) from the kitchen to the dining room. the coefficient of friction static for the table and the floor is (mustatic 0.28) (mukinetic 0.17). what force must be applied to get the table moving with a constant velocity after the initial motion?

Since table is moving on floor with constant speed

So we can say that it must have net force ZERO

it means that applied force is balance by kinetic friction on the table

So we can say

here we can say

now we know that

Now we have friction force as

So here our applied force is same as kinetic friction

pretty sure it's false

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.