Two tractors pull against a 1000 kg log. if the angle of the tractors' chains in relation to each other is 18.0° (each 9.0° from being parallel with the log) , and each tractor pulls with a force of 800 n, what forces will they be able to exert? a. 250 nb. 1520 nc. 1580 nd. 1600 ni'm 80% sure it's c but i don't know how to go about calculating the answer. any is appreciated.

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j