Moving from 0m/s to 25m/s in 8.0s equals an average acceleration

Moving from 0m/s to 25m/s in 8.0s equals an average acceleration of 3.125 m/s^2. You get this through the following steps:

25-0/8-0 = 3.125 m/s^2

since the average acceleration (a) = change in vvelocity over change in time

3.125 m/s^2

Shoutout to: @Mr. Toto

sad!; live

Average acceleration = 3.124 m/s²

Given data:

Initial velocity = 0 m/s

Final velocity = 25 m/s

Time = 8.00 s

Average acceleration = ?

Solution:

Average acceleration = (Final velocity - Initial velocity)/time

By putting values in above formula:

Average acceleration = (25 - 0)/8

                                  = 25/8

                                  = 3.125 m/s²

Hence an object moving from 0m/s to 25m/s of velocity in 8.0s has an average acceleration of 3.125 meter per second square. Acceleration is the rate of change of velocity. And average acceleration is equal to change in final velocity and initial velocity divided by time.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.

what is the actual question though?