Two masses are connected by a string which goes over an ideal pulley as shown in fig. 5-6. block a has a mass of 3.00 kg and can slide along a rough plane inclined 30.0° to the horizontal. the coefficient of kinetic friction between block a and the plane is 0.400. block b has a mass of 2.77 kg. what is the acceleration of the blocks?

The acceleration of the blocks is 0.392 m/s²

Explanation:

Lets revise the newton second low

Newton's second law of motion states that an object will accelerate

when there is a net external force acting on the object

∑ force in direction of motion = mass × acceleration

The system will move by same acceleration

So we will take all the forces acting on blocks to find the acceleration

Assume that the system will move up the plane because the

weight of block B is greater than the component of wight of

block A

At first we must distribute the mass of block A to two components :

One parallel to the plane ⇒ (m1)g sin 30°

One perpendicular to the plane ⇒ (m1)g cos 30°

The forces acting in block A are:

1. Tension (T) acting up in the rope

2. Frictional force (F) acting down (opposite to the direction of motion)

3. The parallel component of the weight acting down (mg sin 30)

According to Newton Low:

T - (m1)g sin(30) - F = (m1)a ⇒ (1), where (m1) is the mass of block A and

"a" is the acceleration of the system

Block b will move up

The force acting on block B are:

1. Tension (T) upward

2. Weight of block B (m2)g downward

According to Newton Low:

(m2)g - T = (m2)a ⇒ (2), where m2 is the mass of block B

Add equations (1) and (2) to eliminate the tension

(m2)g - (m1)g sin(30) - F = (m1 + m2)a ⇒ (3)

Frictional force F = μR, where R is the normal reaction on the block A

R = (m1)g cos30

F = μ (m1) cos30

μ = 0.4 , m1 = 3 , g = 9.8 m/s²

F = (0.4)(3)(9.8) cos30 = 10.184

m2 = 2.77

Substitute the vales in equation (3)

(2.77)(9.8) - (3)(9.8) sin30 - 10.184 = (3 + 2.77)a

27.146 - 14.7 - 10.184 = 5.77 a

2.262 = 5.77 a

Divide both sides by 5.77

a = 0.392 m/s²

The acceleration of the blocks is 0.392 m/s²

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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