Ahockey player hits a puck so that it comes to rest in 9 s after sliding 30 m on the ice. determine (a) the acceleration in terms of ,(4 marks) (b) the initial velocity and acceleration of the puck.(5 marks)

a) Acceleration, a = -u/9, where u is the initial velocity

b) Acceleration = 0.741 m/s², Initial velocity = 6.67 m/s

Explanation:

 We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

a)  We have v = 0 m/s, t = 9 s

 So,    0 = u + a x 9

      Acceleration, a = -u/9, where u is the initial velocity

b) We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 s = 30 m , u = -9a, t =9 s

 So,  

u = -9a = 6.67 m/s

So acceleration = 0.741 m/s², Initial velocity = 6.67 m/s

the moving of the box is a result of centripetal force. think of that  as a car or a truck in this case creates a turn, the force of friction performing upon the turned wheels of the car runs centripetal force obligatory for circular motion for the things inside it.