An 80.0-kg object is falling and experiences a drag force due to air resistance. the magnitude of this drag force depends on its speed, v, and obeys the equation fdrag=(12.0n⋅s/m)v+(4.00n⋅s2/m2)v2. what is the terminal speed of this object?

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force =

Equating both, we have

  So v = 12.58 m/s or v = -15.58 m/s ( not possible)

 So terminal velocity of object = 12.58 m/s    

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

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