To win the game, a place kicker must kick a football from a point 28 m (30.6208 yd) from the goal, and the ball must clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 18 m/s at an angle of 48◦ from the horizontal. the acceleration of gravity is 9.8 m/s 2 . by how much vertical distance does the ball clear the crossbar? answer in units of m.

v = 18cos48 m/s  

So time = distance/speed  

= 28/18cos48  

= 2.3247413  

Resolving vertically, now use s = ut + (0.5)a(t^2)  

Where s is the unknown distance (the height above the GROUND)  

u is initial (vertical) speed = 18sin48  

a = -9.8 m/s (negative since we take upwards as positive)  

t = 2.3247... (what we found previously)  

Putting the numbers into the formula gives 4.616126809  

Take away the height of the goalpost (3.05) = 1.566126809  

= 1.57m above the crossbar.

hope this helps :)

powerful computers now, not then