Apowerful motorcycle can accelerate from rest to 23.8 m/s (53 mi/h) in only 5.90 s. (a) what is its average acceleration in m/s2? m/s2 (b) how far does it travel in that time? m

Let’s use the following equation to determine the acceleration.  

vf = vi + a * t, vi = 0  

29.8 = a * 1.9  

a = 29.8 ÷ 1.9  

The acceleration is approximately 15.68 m/s^2. Let’s use this acceleration in the following equation to determine the distance.  

d = vi * t + ½ * a * t^2, vi = 0  

d = ½ * (29.8 ÷ 1.9) * 1.9^2 = 28.31 meters

hope this helped!

answer; how far out of place which the object finished relative to the starting location;