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Physics, 09.07.2019 04:00 happyabbie23

An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenthesis equals 18 t squaredd(t)=18t^2 feet in the first t seconds. find the average rate of change of distance with respect to time as t changes from t 1t1equals=55 to t 2t2equals=99. this rate is known as the average velocity, or speed.

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