Aball initially at rest rolls down a hill with an acceleration of 3.3 m/s2. if it accelerates for 7.5 s, how far will it move?

  Ball will move 92.8125 meter along the cliff in 7.5 seconds.

Explanation:

We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = 0 m/s, acceleration = 3.3 , we need to calculate displacement when time = 7.5 seconds.

Substituting

  So ball will move 92.8125 meter along the cliff in 7.5 seconds.

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