Acannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (vx) of 50 m/s. how long will it fall?

We have the equation of motion , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 100 m, Initial velocity = 0 m/s, acceleration = 9.81

Substituting

A cannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (Vx) of 50 m/s will take 4.52 seconds to reach the ground.

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm