100j of heat energy are transferred to 80 g of mercury. by how much does the temperature increase?

Given: Heat given to mercury (Q) = 100 J

Mass of mercury (m) = 80 g = 80 × 10⁻³ kg

Specific Heat capacity of mercury (c) = 138 J/kg°C

Let the rise of temperature be Δt

Formula Used:   Q = mcΔt

Here, all alphabets are in their usual meanings.

Calculation:

                          Q = mcΔt

or,                     Δt = Q / mc

or,                     Δt = 100 J /[(80 × 10⁻³ kg)×(138 J/kg°C)]

or,                     Δt = 9.058 °C

or,                     Δt = 9.1 °C

Hence, the required increase in temperature will be 9.1 °C.

probably not if net force is zero

the components of a vector are the parts of the vectors that are to each other.

b perpendicular