Akangaroo jumps straight upward with a velocity of 5.77 m/s. determine the height (to two decimal places) to which the kangaroo jumps.

Initial velocity of kangaroo in upward direction (u) = 5.77

Final velocity at the highest point of the journey (v) = 0

Let the maximum height reached be H.

Acceleration due to gravity = -9.8

Now, using the third equation of motion:

H = 1.698 m

The maximum height reached by kangaroo is 1.7 m.