The satellite s travels around the earth in a circular path with a constant speed of 20 mm> h. if the acceleration is 2.5 m> s2, determine the altitude h. assume the earth's diameter to be 12 713 km.

The altitude of planet = 5989.198 km

Explanation:

    We know that centripetal acceleration, , where v is the velocity and r is the radius. In this case both acceleration and velocity is given, so we can find radius of satellite.

    v =

    a =

 So,  

 We have diameter of earth = 12713 km

        Radius of earth = 12713/2 = 6356.5 km

   The altitude of planet = Radius of planet - radius of earth

                                         = 12345.698 - 6356.5

                                         = 5989.198 km

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

f is prop to m1xm2 double m1 double force