How many electrons move past a fixed reference point every t = 1.15 ps if the current is i = -2.7 μa ?

As per the question,the current amplitude is given as i= -2.7 micro ampere

                                                                                      i.e -2.7 ×

as per the question the time is given as t=1.15s

we know that

                         hence q=i×t

hence the total charge passing through this point is given as

                         q= -2.7×× 1.15

                             = -3.105×

we know that q=ne where n is the number of electrons and e is the charge of electron

we have e= -1.602× coulomb

hence number of electrons n=

                         = 3.105××

                         =1.93820×

answer: i pick a

explanation:

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