The force of attraction between two oppositely charged pith balls is 5.3 × 10-6 newtons. if the charge on the two objects is 6.7 × 10-9 coulombs, what is the distance between the two charges? (k = 9.0 × 109 newton·meter2/coulombs2) a. 2.76 × 10-1 meters b. 7. 0 × 10-1 meters c. 6.7 × 10-1 meters d. 8.2 × 10-1 meters e. 9.6 × 10-1 meters

A.  2.76 × 10-1 meters

Explanation:

The electrostatic force between two charges is given by:

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the distance between the charges

In this problem, we know:

So we can re-arrange the equation to find the distance between the two charges:

Which corresponds to option A, 2.76 × 10-1 meters.

0.863333

86%

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