The driver of a pickup truck going 89.9 km/h applies the brakes giving the truck a uniform deceleration of 5.99 m/s^2 while it travels 19.3 m. a. the velocity of the truck in m/s at the end of this displacement is m/s. b. how much time has elapsed?

(a) First, convert the truck's velocity from km/h to m/s:

Then the velocity after traveling satisfies

where and are the truck's initial velocity and acceleration, respectively. So we have

Taking the square root gives two possible velocities of the same magnitude but in opposite directions. It's technically feasible that over the given displacement, the truck changes its direction and is accelerating back towards its starting position since we're treating the truck as a particle.

(b) When acceleration is constant, average velocity is given by

which tells us that

Plugging in both possible values of we found earlier, we get (if is positive) or (if is negative).

newton's first law of motion

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.