Two cars cover the same distance in a straight line. car a covers the distance at a constant velocity. car b starts from rest and maintains a constant acceleration. both cars cover a distance of 520 m in 223 s. assume that they are moving in the x direction. determine (a) the constant velocity of car a, (b) the final velocity of car b, and (c) the acceleration of car b.

a) For the motion of car with uniform velocity we have , , where s is the displacement, u is the initial velocity, t is the time taken a is the acceleration.

In this case s = 520 m, t = 223 seconds, a =0

Substituting

 The constant velocity of car a = 2.33 m/s

b) We have

s = 520 m, t = 223 seconds, u =0 m/s

Substituting

Now we have v = u+at, where v is the final velocity

Substituting

        v = 0+0.0209*223 = 4.66 m/s

So final velocity of car b = 4.66 m/s

c) Acceleration = 0.0209

a. carbon monoxide from car exhaust

b.particulate matter, such as soot

c.water vapor from a factory smokestack

d.acid rain

these are the answer choices im on that question right now