Acheetah runs at a steady velocity of 60 km/h (16.7 m/s). over a period of 5.0s, the cheetah increases its pace to 95 km/h (26.4 m/s). what is the average acceleration of the cheetah over this period? must show work.

acceleration =( final velocity - initial velocity ) / total time taken

initial velocity of cheetah = 16.7 m/s

final velocity of cheetah = 26.4 m/s

time taken to change speed = 5 s

acceleration =( final velocity - initial velocity ) / total time taken

so acceleration = (26.4 - 16.7) / 5

acceleration = 9.7/5 = 1.94

the average acceleration of the cheetah over this period is 1.94 m/s²

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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i believe the answer would be:

d. violin, clarinet, french horn, and tuba