An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 14.0 m if her initial speed is 2.20 m/s. what is the free-fall acceleration on the planet? (ignore air resistance.)

We have the equation of motion

                          , where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

In this case initial velocity = 2.20 m/s, final velocity = 0 m/s, displacement = 14 m

On substitution we will get 0 =

On solving we can find the acceleration value as -0.173

So free fall acceleration = 0.173

attach the statements so i can answer : )

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000