Aball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2 g. how far from the bottom of the chute does the ball land?

The ball launched up a semicircular chute is far from the bottom of the chute.

Given to us

Centripetal acceleration = 2g,

y₀ = 2R

= -g

We know that the centripetal acceleration can be written as,

Substituting the value of α,

We can write the formula for the time of free fall,

substitute the values we get,

Hence, the ball is far from the bottom of the chute.

Learn more about Centripetal acceleration:

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the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: