Atourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.8 m/s. the car is a distance d away. the bear is 22 m behind the tourist and running at 6.3 m/s. the tourist reaches the car safely. what is the maximum possible value for d?

The maximum possible value for d is 33.4 m.

The bear chases the tourist with a speed v₁ and the tourist runs with a speed v₂. The distance between the tourist and the car is d and the distance between the tourist and the bear is 22 m. for the tourist to reach the car safely, he should cover the distance d in the same time as the bear, which covers a distance d+22 m.

Therefore,

Substitute 3.8m/s for v₂ and 6.3 m/s for v₁. Solve for d.

The maximum distance between the tourist and his car, for him to be safe from the chasing bear is 33.4 m.

talk back to him about the sport and show him your expertise or leave the room

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.