How many electrons should be removed from an initially uncharged spherical conductor of radius 0.200 m to produce a potential of 5.50 kv at the surface?

To calculate the number of electrons from spherical conductor first we use the formula,

Here, k is a constant with a value of , q is the charge and r is the radius and its value of 0.200 m.

Substituting these value in above formula, we get  

or                

Now number of electron,

Hence, the number of electrons to be removed from conductor would be

Solution:

Potential is defined as

V = kq/r  

=> q= Vr/k  

= 5500 * 0.2 / 9 x 10^9 C  

= (110/9) x 10^-7  

If n = no. of electrons to be removed

So,  

n x 1.6 x 10^-19  

Therefore,

n=v/q

=> n = (110/14.4) x 10^12 electrons  

= 7.6382 x 10^12 electrons.  

This will leave an equal amount of positive charge in protons and produce the give potential on the surface of the sphere.

true

explanation:

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: