The aluminum foil in a package containing 75 square feet of foil weighs 12 ounces. aluminum has a density of 2.70 g/ cm3. what is the approximate thickness of the foil in mm?

Solution:

Since we know that 1 ounce=28.4g/oz

So for 12 oz  X  28.4 g/oz  =  340.8 g

And,

 340.8 g  X  1cm3/2.7g  =  126.22 cm3

Again,

75 ft2  X  12 in/ft  X  12 in/ft  X  2.54 cm/in  X  2.54 cm/in  =  69,677.28 cm2  

(Here ft^2=ft*ft)

Now,

69,677.28 cm2  X Thickness  =  126.22 cm3

Finally Solve for Thickness: 126.22 cm3 / 69,677.28 cm2  =  0.00181 cm

Thus for mm we have to:

0.00181 cm  X  10 mm/1 cm  =  0.0181 mm.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force