Acar traveling at 22.4 m/s skids to a stop in 2.25s. determine the skidding distance of the car

Hello!

A car traveling at 22.4 m/s skids to a stop in 2.25 s. Determine the skidding distance of the car

We have the following data:

a (acceleration) = ? (in m/s²)

t (time) = 2.25 s

Vf (final velocity) = 22.4 m/s

Vi (initial velocity) = 0 m/s

We apply the data to the formula of the hourly function of the velocity, let's see:

*** The distance traveled ?  

We have the following data:  

Vi (initial velocity) = 0 m/s  

t (time) = 2.25 s  

a (average acceleration) = 9.955 m/s²  

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

*** Another way to solve:

We have the following data:  

Vf (final velocity) = 22.4 m/s

Vi (initial velocity) = 0 m/s  

a (average acceleration) = 9.955 m/s²  

d (distance interval) = ? (in m)

Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:

________________________

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6