An iron block of mass 18 kg is heated from 285 k to 318 k. if 267.3 kj is required, what is the specific heat of iron

q = mcΔT

where, q = heat required in Joules

m = mass in grams

c = specific heat in joules/gram °C

ΔT = change in temperature = Final temperature(T₂)-Initial Temperature (T₁)

Given, q=267.3 kJ=267300 Joules

m=18kg=18000 gram

ΔT=318-285= 33K = 33°C

Rearranging formula, c=

c=

c=0.45 joules/gram °C

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