Aforce of 83 newtons is applied to a wire with a diameter of 0.5 mm. what is the tensile stress (in n/m2) in the wire? do not include units with the answer.

Tensile stress=4.23 x 10⁸ N/m²

Explanation:

Tensile stress= F/a

F= force= 83 N

a= area= πr² where r is the radius

d= diameter= 0.5 mm

r= d/2=0.5/2=0.25=0.00025 m

a=π (0.00025 )²= 1.963 x 10⁻⁷ m²

Tensile stress= 83/(1.963 x 10⁻⁷ )

Tensile stress=4.23 x 10⁸ N/m²

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