An electron moves across earth's equator at a speed of 2.5 106 m/s and in a direction 35° n of e. at this point, earth's magnetic field has a direction due north, is parallel to the surface, and has a magnitude of 0.10 t. what is the force acting on the elec- tron due to its interaction with earth's magnetic field?

The force acting on the electron is 0.57*10^(-17) N.

The force on the electron is calculated by the Lauren law.

F=BQvsinθ

F=0.10*〖10〗^(-4)*1.6*〖10〗^(-19)*2.5*10^(6)sin35°

=0.57*10^(-17) N

Therefore the force on the electron is 0.57*10^(-17) N

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.