You are initially at rest in your car. at time t = 0, a truck passes you moving at 25.0 m/s. you then immediately begin to accelerate at 3.00 m/s² in the same direction the truck is moving. if you maintain this acceleration, and the truck maintains its speed, when will you overtake the truck?

Let the car will overtake the truck after time 't'. In this time, the distance cover by the car is equal to the distance cover by the truck.

Distance cover by the truck in time 't' = Speed of the truck× time = 25t m

Distance cover by the car can be calculated using the second equation of motion, that is

As, the car started from the rest its initial velocity is zero.

Acceleration of the car= 3 m/s²

∴ Distance cover by the car = 0×t +

= m

Equating the distances cover by the car and the truck, we get

t= = 16.66 s

Hence, the car will overtake the truck in 16.66 s.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it