** a point charge of 6.0 c is placed 5.0 mm from a rod that has an electric field of 2.4 n/c. the electric potential energy of the point charge (rounded to two significant figures) is j.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

it was given as a lesson and guide for prayer.

false

hope this : d