Asky diver jumps out of an airplane at a height of 5010 ft. if her parachute does not open until she reaches 1010 ft, what is her velocity (in ft/s) at that point if air resistance is neglected?

Given:

Height from which diver jumps h(i)=5010 ft

Height from which diver open the parachute h(f)=5010 ft

calculate the net height h= h(i)-h(f)

substitute the values in the above equation

h= 5010-1010= 4000 ft

calculate the velocity of the diver at the net height.

here g is acceleration due to gravity = 32.2 ft per second square

h is the net height

substitute the values in the above equation

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

pretty sure it's false