Abaseball is  thrown with a horizontal velocity of 40.20 m/s and no vertical velocity. if  the ball  leaves the pitcher's hand  at a height of 2.000 m above the ground, how far will the ball travel before it hits the ground? (air resistance is negligible.) a.12.68 m b.16.48 m c.25.73 m d.51.46 m

Option (c) is correct.

Explanation:

initial velocity along vertical=0

velocity along horizontal Vx=40.20 m/s

acceleration along the vertical=9.8 m/s²

displacement along vertical,h=2 m

using the kinematic equation

h= vi*t + 1/2 g t²

2=0(t) + 1/2 (9.8)t²

t²=0.408

t=0.639 s

now the displacement along vertical= x= Vx* t

x=40.20 (0.639)

x=25.73 m

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.