At what temperature is the average kinetic energy of an atom in helium gas equal to 6.21 x 10-21 j?

The average kinetic energy of an atom in helium gas at temperature T is given by,

K.E=

here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹

Given, K.E= 6.21×10⁻²¹ J

Substituting the values,

T= 300 K

Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

spare some change and give it to the poor

explanation:

plz : ((