In a hydraulic system, piston 1 has a surface area of 100 cm2, and piston 2 has a surface area of 900 cm2. a force of 150 n is exerted on piston 1 of the hydraulic lift. what force will be exerted on piston 2?

In the hydraulic system, the pressure is equal on each piston. The force exerted on the second piston is 1350 N.

Assume, In the hydraulic system, the pressure is equal on each piston.

P1 = P2

So,

Force = Pressure x Area

Where,

F1 - Force exerted on first piston = 150 N

A1 = area of first piston = 100

A2 = area of the second piston = 900

Put the values and solve for F2,

Therefore, the force exerted on the second piston is 1350 N.

To know more about surface area,

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answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )