Aforce of 60 n is used to stretch two springs that are initially the same length. spring a has a spring constant of 4 n/m, and spring b has a spring constant of 5 n/m. how do the lengths of the springs compare? how do the lengths of the springs compare? a. spring b is 1 m longer than spring a because 5 – 4 = 1. b. spring a is the same length as spring b because 60 – 60 = 0. c. spring b is 60 m longer than spring a because 300 – 240 = 60. d. spring a is 3 m longer than spring b because 15 – 12 = 3. i don't need the answer the correct answer is d

We can calculate the length of each spring by using the relationship:

where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)

Re-arranging the equation, we have


The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is

Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is


Therefore, the correct answer is
D.Spring A is 3 m longer than spring B because 15 – 12 = 3.