Given that a 5.0 ω resistor, a 9.0 ω resistor, and a 13.0 ω resistor are connected in series with a 24.0 v battery, calculate the current in each resistor.

Current, I = 0.89 A

Explanation:

It is given that, three resistors are connected in series. Their equivalent is given by :

Voltage of battery, V = 24 V

In series combination the current flowing across each resistor is same. The current can be calculated using Ohm's law :

I = 0.89 A

So, the current flowing in each resistor is 0.89 A. Hence, this is the required solution.                                

no

explanation:

no i dont know how to solve this you should probably try to google the answer