What is the critical angle for light traveling from water (n=1.333) into ice (n=1.309)? a. 79.11º b. 69.12º c. 59.08º d. 49.15º

The critical angle is the angle of incident in the optically dense media that produces the angle of refraction as 90°.

sin c =1/n, where n is the refractive index and c is the critical angle. 
Also, n1sinФ1=n2sinФ2

In this case we have,
1.33×sinc = 1.309×sin90°     Where c is the critical angle. 

sin c =1.309/1.33

sin c = 0.981995498

      c = 79.11°  

The objects do not reach terminal velocity         there is not enough time from the time the object falls from when it hits the ground to achieve terminal velocity. an object must be placed higher to achieve terminal velocity in order to be in free fall.