If you balance the equation below, what should be the coefficient for rubidium(rb)? rb(s) + cl2(g) > rbcl(s) a. 4 b. 2 c. 1 d. 3

The correct answer is B) 2.

Note that the correctly balanced reaction should also have a factor 2 in front of RbCl(s). In fact, the balanced reaction is

This way, we have:
- 2 atoms of Rb on the left side, and 2 atoms of Rb on the right side
- 2 atoms of Cl on the left side, and 2 atoms of Cl on the right side
so, the reaction is balanced.