An ac generator has a maximum emf output of 155 v. a. find the rms emf output. b. find the rms current in the circuit when the generator is connected to a 53 ω resistor.

Vp = 155 V
R = 53 ω

(a) RMS emf output

Vrms = 0.7071Vp = 0.7071*155 = 109.6 V

(b) RMS current
From ohm's law,
Vrms = IrmsR => Irms = Vrms/R = 109.6/53 = 2.07 Amps

A) For an ac generator, the rms value of the voltage is given by:

where  is the peak value of the voltage.

For the generator in our problem, the peak value is , therefore the rms value of the voltage is


b) We can find the rms current in the circuit by using Ohm's law, which is also valid when using the rms values of the current and the voltage:

where R is the resistance conncected to generator. If we use , we find

Sorry i don’t know what to do