At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. what is the volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa?

V = 1.66 L

Explanation:

As we know that at the depth of 10 m the volume of the lungs of diver is given as

V = 2.40 L

Temperature = 32 degree C

Pressure = 101.30 kPa

Now we have change the values of pressure and temperature

Pressure = 141.20 kPa

Temperature = 21 degree C

Now we can use idea gas equation to solve this

so we have

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer